Difference between revisions of "Removing a user from all DLs on a server"

 
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=== <h1>Removing a user from all DLs on a server</h1>===
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=Removing a user from all DLs on a server=
 
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{{KB|{{ZC}}|{{ZCS 8.8}}|{{ZCS 8.7}}|{{ZCS 8.6}}|{{ZCS 8.5}}|}}
  
<h2>Problem:</h2> Removing a user from all DLs on a server
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====Problem====
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Removing a user from all DLs on a server
  
 
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====Solution====
<h2>Solution:</h2>
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We can do this using a combination of zmsoap and zmprov
 
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* 'zmsoap' will get a list of all the distribution lists the user is a member of. So for 'user@example.com':
We can do this using a combination of zmsoap and zmprov<br><br>
 
'''1).''''zmsoap' will get a list of all the distribution lists the user is a member of. So for 'user@example.com':
 
 
  zmsoap -z GetAccountMembershipRequest/account=user@example.com @by=name
 
  zmsoap -z GetAccountMembershipRequest/account=user@example.com @by=name
  
'''2).'''Use this to make a 'zmprov' script that will run 'zmprov rdlm dl@example.com user@example.com' for all the DLs:
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* Use this to make a 'zmprov' script that will run 'zmprov rdlm dl@example.com user@example.com' for all the DLs:
 
  zmsoap -z GetAccountMembershipRequest/account=user@example.com @by=name | sed -n 's/.*name="\(.[^"]*\)".*/rdlm \1 user@example.com/p' > /tmp/rdlm.zmprov
 
  zmsoap -z GetAccountMembershipRequest/account=user@example.com @by=name | sed -n 's/.*name="\(.[^"]*\)".*/rdlm \1 user@example.com/p' > /tmp/rdlm.zmprov
  
 
The above creates a file '/tmp/rdlm.zmprov', which contains multiple lines in the form of 'rdlm dl@example.com user@example.com'.
 
The above creates a file '/tmp/rdlm.zmprov', which contains multiple lines in the form of 'rdlm dl@example.com user@example.com'.
  
'''3).'''This file is then 'fed' into zmprov, like so, removing the user from all the DLs:
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* This file is then inputted to zmprov, removing the user from all the DLs:
 
  zmprov < /tmp/rdlm.zmprov  
 
  zmprov < /tmp/rdlm.zmprov  
  
  
 
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{{Article Footer|ZCS 8.8, 8.7, 8.6|2018-05-21}}
Submitted by:  Shashank Tewari
 

Latest revision as of 13:04, 21 May 2018

Removing a user from all DLs on a server


   KB 23319        Last updated on 2018-05-21  




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Problem

Removing a user from all DLs on a server

Solution

We can do this using a combination of zmsoap and zmprov

  • 'zmsoap' will get a list of all the distribution lists the user is a member of. So for 'user@example.com':
zmsoap -z GetAccountMembershipRequest/account=user@example.com @by=name
  • Use this to make a 'zmprov' script that will run 'zmprov rdlm dl@example.com user@example.com' for all the DLs:
zmsoap -z GetAccountMembershipRequest/account=user@example.com @by=name | sed -n 's/.*name="\(.[^"]*\)".*/rdlm \1 user@example.com/p' > /tmp/rdlm.zmprov

The above creates a file '/tmp/rdlm.zmprov', which contains multiple lines in the form of 'rdlm dl@example.com user@example.com'.

  • This file is then inputted to zmprov, removing the user from all the DLs:
zmprov < /tmp/rdlm.zmprov 


Verified Against: ZCS 8.8, 8.7, 8.6 Date Created: 2018-05-21
Article ID: https://wiki.zimbra.com/index.php?title=Removing_a_user_from_all_DLs_on_a_server Date Modified: 2018-05-21



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